Question

√2x² + 4x + 2√2 = 0 find the value of discriminant​

Answer 1

Answer:

ANSWER IS 0

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 4x + 2 \sqrt{2}$

a=✓2 , b=4 and c=2✓2

D=b^2-4ac

$d = {4}^{2} - 4 \times \sqrt{2} \times 2 \sqrt{2}$

$16 - 16$

$= 0$

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Answer 2

✞︎ Given :-

➪︎ √2x^2 + 4x + 2√2

We know that ,

$discriminant = {b}^{2} - 4ac$

Here ,

a = √2 ; b = 4 ; c = 2√2

Substituting the values , we get

${4}^{2} - 4( \sqrt{2} )(2 \sqrt{2} )$

$16 - 4(2 \times ( { \sqrt{2}) }^{2}$

$16 - 4 \times 4$

$16 - 16 = 0$

➪︎ Discriminant ( ∆ ) = 0

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