Question

2x² + 4x + 2√2 = 0
plz answer me step by step
it's too urgent ​

Answer 1

$x = \frac{ - b± \sqrt{ {b }^{2} - 4ac } }{2a} \\ here \: a = 2 .\: \: b = - 4. \: \: c = 2 \sqrt{2} \\ = > x = \frac{4± \sqrt{16 - 4 \times 2 \times 2 \sqrt{2} } }{2 \times 2} \\ = > x = \frac{4± 4 \sqrt{1 - \sqrt{2} } }{4} \\ = > x = 1± \sqrt{1 - \sqrt{2} }$

As you know √2 > 1 , so the roots are imagenary.