Question

✓2x²+ 4x +2root 2 = 0. solve by factorisation​

Answer 1

2x² - 2√2x + 1 = 0

2x² - √2x - √2x + 1 = 0

√2x ( √2x - 1 ) - 1 ( √2x - 1 ) = 0

( √2x - 1 ) ( √2x - 1 ) = 0


* ( √2x - 1 ) = 0
x = 1/√2

* ( √2x - 1 ) = 0
x = 1/√2

Answer 2

$✓2x²+ 4x +2✓2 =>0$

$✓2x²+ 2x+2x+2✓2 =>0$

$✓2x²(x+✓2)2(x+✓2)=>0$

$(✓2x+2)(x+✓2)=>0$

$.: ,(✓2x+2)=>4$

$where$$x=>-✓2$

$.: ,(x+✓2)=>0$

Let's check

$(✓2x+2)(x+✓2)=>0$

$now$$put$ $values$

$(4)(0)=>0$

$hence,verified$

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