Question

2x²-4x+3=0 by completing square​

Answer 1

Here is your answer~

sri Dharacharya method

x=4+-√16-24/4

x=4+√-8÷4

x=2(2+√-2)÷4

X=(2+√-2)÷2

x=1,-1/√2

Answer 2

divide the equation by the coefficient of x^2

${x}^{2} - 2x + \frac{3}{2} = 0 \\ {x}^{2} - 2x = - \frac{3}{2} \\ add \: {1}^{2} on \: both \: side \\ {x}^{2} - 2x + 1 = \frac{3}{2} + 1 \\ {(x - 1)}^{2} = \frac{5}{2} \\ x - 1 = \sqrt{ \frac{5}{2} } \\ x = \sqrt{ \frac{5}{2} } + 1$