Question

2x² - 4x +3=0 solve by quadratic formula method​

Answer 1

Answer:

$\frac{\left(4+\sqrt{-8}\right)}{4}$ and $\frac{\left(4-\sqrt{-8}\right)}{4}$ are the roots.

Step-by-step explanation:

$2x^2-4x+3=0$

Here, writing the above equation in the form of $ax^2+bx+c=0$,

$a=2\\b=-4\\c=3$

Hence, the roots are: $\frac{-b+\sqrt{b^{2}-4ac}}{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac}}{2a}$

Hence, the first root is: $\frac{\left(4+\sqrt{16-24}\right)}{4}$

That is, $\frac{\left(4+\sqrt{-8}\right)}{4}$

The second root is:

$\frac{\left(4-\sqrt{-8}\right)}{4}$

This equation has imaginary roots.

Hope it helps.