Question

2x² – 4x + 6 in the form  p(x – q)²+ r where p, q and r are constants to be found. Hence state the least value of  2x2 – 4x + 6 and the value of x at which this occurs.     ​

Answer 1

Answer:

2x

2

+4x+3=0

Let the roots be α,β

So α+β=

2

−4

=−2.