Math, asked by pvsaindane, 10 hours ago

2x2-5x+12 ही बाहुबली सहगुणक टिंब टिंब कशी लिहितात. A) { 2,-5,12} B) {2, 5, 12,} C) { 2,5,12, } D) {2, -5 -12} Answer A = { 2,-5,12}​

Answers

Answered by gagori7
0

Answer:

p=7,q=−18

Let, f(x)=x

3

+10x

2

+px+q

Given : (x+2) and (x−1) are factors of f(x)

∴f(−2)=0,f(1)=0

f(−2)=(−2)

3

+10(−2)

2

+p(−2)+q

⟹0=−8+40−2p+q

⟹2p−q=32 -----------(i)

f(1)=(1)

3

+10(1)

2

+p(1)+q

⟹0=1+10+p+q

⟹p+q=−11 ----------(ii)

Adding (i) and (ii),

we get,

2p−q+p+q=32−11

⟹3p=21

⟹p=7

Substituting p=7 in (ii), we get,

7+q=−11

⟹q=−11−7=−18

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