Question

2x²+5x+2=0 solve by formula method
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Answer 1

$2 {x}^{2} + 5x + 2 = 0 \\ 2 {x}^{2} + 4x + x + 2 = 0 \\ 2x(x + 2) + 1(x + 2) \\ (2x + 1)(x + 2)$

$\: we \: can \: do \: it \: by \: shridharacharya \: formula \: also\\ \frac{ - b + \: or \: - \: \sqrt{ {b}^{2} - 4ac} }{2a} \\ \frac{ - 5 \: + \: or \: - \sqrt{25 - 4(2)(2)} }{4} \\ \frac{ - 5 \: + \: or \: - \: \sqrt{9} }{4} \\ \frac{ - 5 \: + \: or \: - 3}{4} \\ \frac{ - 5 - 3}{4} \\ \frac{ - 8}{4} = - 2 \: (one \: root \: of \: this \: equation) \\ and \: \frac{ - 5 + 3}{4} = \frac{ - 1}{2} (second \: root \: of \: this \: equation)$

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