Question

(2x²+5x-3)/(X+3)
please tell me the answer with details ​

Answer 1

Mid Term Factorisation

Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 5 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1

-1 + 6 = 5 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 6

2x2 - 1x + 6x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (2x-1)

Add up the last 2 terms, pulling out common factors :

3 • (2x-1)

Step-5 : Add up the four terms of step 4 :

(x+3) • (2x-1)

Which is the desired factorization

Final result :

(2x - 1) • (x + 3)

——————————————————

x - 3

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Answer 2

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$= (2x² + 5x - 3)/(x + 3)$

$= (2x² - x + 6x - 3)/(x + 3)$

$= (x + 3)(2x - 1)/(x + 3)$

$= 2x - 1$

Hope it helps uh :)