(2x² - 5y) (5x + 2y²); x = 2 y = - 1
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x = 2
y = -1
(2x² - 5y) (5x + 2y²)
= (2 × 2² - 5 × -1) (5 × 2 + 2 × -1²)
= (2 × 2² - 5 × -1) × (5 × 2 + 2 × -1²)
= (2 × 4 - 5 × -1) × (5 × 2 + 2 × -1)
= 8 - 5 × 10 + (-2)
= 3 × 10 - 2
= 30 - 2
= 28
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