(2x²-5y²) : xy =1:3, find the value of x and y.
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4
x=√5 &
y=3√5/5
may its help
y=3√5/5
may its help
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Answer:
Given (2x² - 5y²) : xy = 1 : 3
(2x² - 5y²) / xy = 1 / 3
6x² - 15y² = xy
6x²- xy - 15y² = 0
(3x - 5y) (2x + 3y) = 0
3x - 5y = 0. or 2x + 3y = 0
3x = 5y or 2x = -3y
x / y = 5 / 3 or x / y = -3 / 2.
But x : y is not defined for negative values of x or y
Hence, x : y = 5 : 3.
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