Question

2x²-6x+3=0
Solve by formule method​

Answer 1

Step-by-step explanation:

2x² - 6x + 3

here

• a = 2
• b = -6
• c = 3

x = -b ± √(b² - 4ac) / 2a

• x = [ -(-6) ± √((-6)² - 4*2*3) ] / 2*2
• x = [ 6 ± √(36 - 24) ] / 4
• x = [ 6 ± √12 ] / 4
• x = [ 6 ± 2√3 ] / 4
• x = 2[3 ± √3] / 4
• x = [3 ± √3] / 2

$\large \: \bf \: x = \frac{3 + \sqrt{3} }{2} \: \: or \: \: \frac{3 - \sqrt{3} }{2}$