Question

2x²-7x-3=0. by squaring roots method​

Answer 1

Step-by-step explanation:

I think your question is wrong your question must be the given one because then only answer comes

$2 {x}^{2} - 7x + 3 = 0 \\ = > 2 {x}^{2} - 6x - x + 3 = 0 \\ = > 2x(x - 3) - 1(x - 3) = 0 \\ = > (2x - 1)(x - 3) = 0 \\ = > 2x - 1 = 0 \: \: \: \: \: or \: \: \: \: \: x - 3 = 0 \\ = > x = \frac{1}{2} \: \: \: \: \: or \: \: \: \: \: x = 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: the \: solutons \: are \: \frac{1}{2} \: and \: 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{1}{2} and \: 3$

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Answer 2

Answer:

I think your question is wrong