Question

2x²-7x-39=0
pls reply me fast pls help​

Answer 1

Answer:

${2x}^{2} - 7x - 39 = 0 \\ - 39 \times 2 = 78 \\ - 78 = 6 \times - 13 \\ - 13 + 6 = - 7 \\ {2x}^{2} - 13x + 6x - 39 = 0 \\ {2x}^{2} + 6x - 13x - 39 = 0 \\ 2x(x + 3) - 13(x + 3) = 0 \\ (x + 3)(2x - 13) = 0 \\ x + 3 = 0 \\ x = 0 - 3 \\ x = - 3 \\ 2x - 13 = 0 \\ 2x = 0 + 13 \\ 2x = 13 \\ x = \frac{13}{2} \\ x = 6.5$