Question

√2x² + 7x + 5√2 = 0​

Answer 1

Step-by-step explanation:

√2x²+2x+5x+5√2

√2x(x+√2)+5(x+√2)

(√2x+5)(x+√2)

Answer 2

Ans.

$\sqrt{2 {x}^{2} } + 7x \: + \sqrt[5]{2} \\ \\ \sqrt{2 {x}^{2} } + 2x + 5x + \sqrt[5]{2} \\ \\ \sqrt{2x} ( x + \sqrt{2} ) + 5(x + \sqrt{2} ) \\ \\ ( \sqrt{2x} \: + 5)(x + \sqrt{2} )$

Rules to solve .☺️

1. First multiple 1st no.with last number .

i.e √2x²*5√2=> 10

2.....Then split middle term i.e 7x in that way so that after adding/subtraction answer will be 7x or after multiple the numbers answer would be 10x

.i.e 2x+5x=7x .........or.......2x*5x=10x

3.Then find common factors refer above .☺️

$\color{red} \bf{extra \: information}$

If numbers of zeroes need to find ...

then ÷

√2x+5=0.................x+√2=0

√2x=-5...................x={-√2)

$x = \frac{ - 5}{ \sqrt{2} } \: \: \: \: \\ \\ x = - \sqrt{2}$

$<marquee > hope its helps you$