Math, asked by bandai, 8 months ago

√2x² + 7x + 5√2 = 0​

Answers

Answered by Hiteshbehera74
14

 \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  = 0 \\  \sqrt{2}  {x}^{2}  + 2x + 5x + 5 \sqrt{2}  = 0 \\  \sqrt{2} x(x +  \sqrt{2} ) + 5(x +  \sqrt{2} ) = 0 \\ (x +  \sqrt{2} )( \sqrt{2} x + 5) = 0 \\  \\ x =  -  \sqrt{2}  \: or \: x =  -  \frac{5}{ \sqrt{2} }

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