Question

√2x2 + 7x + 5√2 = 0 find roots by factorization​

Answer 1

Answer:

i hope it will help you thank u

Answer 2

Answer:

x = -5/$\sqrt{2$ or -1

Step-by-step explanation:

$\sqrt{2x^{2} } + 7x + 5 \sqrt{2} = 0 \sqrt{2x^{2} } + 5x +2x + 5 \sqrt{2}\\ = 0\\\sqrt{2x} } (\sqrt{2x} }+ 5 ) + \sqrt{2} } (\sqrt{2x} } + 5) = 0\\(\sqrt{2x} }+5) (\sqrt{2x} } + \sqrt{2} } )\\\sqrt{2x} } + 5 = 0 or \sqrt{2x} } + \sqrt{2} } = 0\\\sqrt{2x} } = - 5 or \sqrt{2x} } = - \sqrt{2} }\\x = -5/\sqrt{2} } or x = -\sqrt{2} } / \sqrt{2} } = -1$