Question

√2x² +7x +5√2=0. Solve quadratic equation by factorization method
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Answer 1

Answer:

(1+√2x)(√2x+5)=0

x= -1/√2 , -5√2/2

Step-by-step explanation:

√2x² +7x +5√2=0

√2x² +2x +5x+5√2=0

√2x(1+√2x)+5(1+√2x)=0

(1+√2x)(√2x+5)=0

Answer 2

Answer :

√2x² +7x +5√2 = 0

Concept

• when the first term of quadratic equation have numerical then we the number multiply by the last number of quadratic equation.

According to the concept

multiplying √2 × 5√2

the equation will be

x² + 7x + 10 (√2×5√2= 5×2=10)

Factorisation

x² + 5x + 2x + 10

x ( x + 5 ) + 2 ( x + 5 )

(x + 5) (x + 2)

x + 5 = 0

x = -5

x + 2 = 0

x = -2

Factor of the quadratic equation are

x = -5

x = -2