2x² -7x+ 5 for
1/α^2+1/β^2
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Step-by-step explanation:
let a,b be roots of given equation
a+b = 7/2
ab = 5/2
1/a²+1/b² = a²+b²/ a²b² = (a+b)²-2ab/(ab)²
= (7/2)²-2×5/2 / (5/2)²
= 49/4 -5/(25/4) = 49-20 /25 = 29/25
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