Question

2x² + √7x-7=0 solve this using quadratic formula​

Answer 1

Answer:

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Answer 2

$\huge\rm\underline\green{Solution:-}$

$a = 2 \: and \: b = \sqrt{7} \: and \: c = - 7 \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \: (or) \: \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ = > x = \frac{ - \sqrt{7} + \sqrt{7 - 4(2)( - 7) } }{2(2)} \: (or) \: x = \frac{ - \sqrt{7} - \sqrt{7 - 4(2)( - 7)} }{2(2)} \\ \\ = > x = \frac{ - \sqrt{7} + \sqrt{63} }{4} \: (or) \: x = \frac{ - \sqrt{7} - \sqrt{63} }{4} \\ \\ = > x = \frac{ - \sqrt{7} + 3 \sqrt{7} }{4} \: (or) \: x = \frac{ \sqrt{7} - 3 \sqrt{7} }{4} \\ \\ = > x = \frac{2 \sqrt{7} }{4} \: (or) \: x = \frac{ - 2 \sqrt{7} }{4} \\ \\ = > x = \frac{ \sqrt{7} }{2} \: (or) \: x = \frac{ - \sqrt{7} }{2}$