Question

2x²-8x+6=0 find the value of x

Answer 1

Hey user here is your answer.....

--->Given equation- 2x^2-8x+6

---->By middle term splitting


◆2x^2-6x-2x+6

◆Taking common

◆2x(x-3)-2(x-3)

◆(2x-2)(x-3)

◆2x-2=0
&
◆x-3=0

◆x=2/2=1

◆x=3



Thanks☺️

Answer 2

The value of $x$ is $3$ and $1$

Given quadratic equation is $2x^2-8x+6=0$

Find the value of $x$.

Solution-In algebra, a quadratic equation is any equation that can be rearranged in standard form as $ax^{2}+bx+c=0$ where x represents an unknown, and a, b, and c represent known numbers, where $a \neq 0.$ If $a = 0$, then the equation is linear, not quadratic, as there is no $ax^2$ term.

In mathematics, factorization or factoring consists of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind. For example, $3 \times 5$ is a factorization of the integer 15, and is a factorization of the polynomial $x^2-4.$

Given equation $2x^2-8x+6=0$

$2x^2-(6+2)x+6=0$

$2x^2-6x-2x+6=0$

$2x(x-3)-2(x-3)=0$

$(x-3)(2x-2)=0\\x=3,x=1$

So, the value of $x$ is $3$ and $1$

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