Question

2x²-8x+7=0
solve the equation

Answer 1

Answer:

2x×2x-8x+7=0

4x-8x+7=0

-4x=7

x=7/-4

$\frac{7}{ - 4}$

Answer 2

Answer:

Heya! Answer is here

Step-by-step explanation:

2x²-8x+7=0

Comparing 2x²-8x+7=0 with ax²+bx+c=0, we get

a= 2, b= -8 and c = 7

Now,

b²-4ac = (-8)²-4×2×7

= 64 - 56

= 8

$x = \frac{ - b \: ± \: \sqrt{ {b}^{2} - 4ac } }{2a}$

... (Formula)

$x = \frac{ - ( - 8)± \sqrt{8} }{2 \times 2}$

... (Substituting the values )

$x = \frac{8± 2 \sqrt{2} }{4}$

$x = 2± \frac{ \sqrt{2} }{2}$

$x = 2± \frac{1}{ \sqrt{2} }$

Ans. The roots of the given quadratic equation are

$2 + \frac{1}{ \sqrt{2} } \: \: \: and \: \: \: 2 - \frac{1}{ \sqrt{2} }$