Question

2x²-9x-10=0 factors?

Answer 1

Solution :

2x² - 9x - 10 = 0

a = 2

b = -9

c = -10

Firstly, let's find its roots by using quadratic formula,

Roots = { - b ± √(b² - 4ac)}/2a

Roots = { - (-9) ± √(-9² - 4×2×-10)}/2 × 2

Roots = (9±√161)/4

Roots = (9 + √161)/4 and (9-√161)/4

Factors :

• [ x - ( 9 + √161)/4 ]

• [ x - ( 9 - √161)/4 ]

Answer 2

⠀|| ☆.ANSWER.☆ ||

FIND Here:-

• Factor of ( 2x²-9x-10) = 0

EXPLANATION:-

=> (2X²-9X-10) = 0

General quadratic equation

ax² + bx + c = 0

[ USING DHARACHARYA FORMULA ]

=> x = [ {-b ± √( b² - 4ac)}/2a] ......(1)

where,

• a = 2,
• b = -9,
• c = -10.

Keep value in equation (1)

=> x = [{ -(-9) ± √{ (-9)² - (4 × 2 × -10) }}/(2×2) ]

=> x = [ { 9 ± √ ( 81 +80 )}/4 ]

=> x = [ { 9 ±√(161)}/4 ]

Case(1):-

• First ,take positive sign

=>x = [ { 9 + √(161) } / 4 ]

Case(2):-

• Second, take negative sign

=> x = [ { 9 + √(161) } / 4 ]

Factor of ( 2x² - 9x -10 = 0 ) :-

• x - [ { 9 + √(161) } / 4 ]
• x - [ { 9 + √(161) } / 4 ]

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