Question

2x²-9x+7=0 Quadratic Equations​

Answer 1

Answer:

$\huge\boxed{x=1\ \vee\ x=3.5}$

Step-by-step explanation:

$2x^2-9x+7=0\\\\2x^2-2x-7x+7=0\\\\2x(x-1)-7(x-1)=0\\\\(x-1)(2x-7)=0\iff x-1=0\ \vee\ 2x-7=0\\\\x-1=0\\\boxed{x=1}\\\\2x-7=0\\2x=7\\\boxed{x=3.5}$

Answer 2

Answer:

2x^2 -x (7+2) +7=0

2x^2 -7x-2x+7=0

x(2x-7) -1(2x-7) =0

(2x-7) (x-1)=0

either or

2x-7=0 x-1=0

x=7/2 x=1