Question

2x² - kx + 1 - 0 find value of K​

Answer 1

Answer:

√8

Step-by-step explanation:

i think ur ques is incomplete

but if it also have equal roots then see below

2x²-kx+1=0

a=2

b=k

c=1

Given,the roots are equal

so it means that the determinant (d) =0

d=b²-4ac

0=b²-4ac

0=(k)²-(4)(2)(1)

0=k²-8

8=k²

√8=k

Hence, the value of k is √8

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