Question

2x²+kx+14=0 for real solution​

Answer 1

Step-by-step explanation:

Let the polynomial be p(x).

If 2 is a zero, then p(2)=0.

p(x)=2x

2

+kx−14

p(2)=2(2

2

)+2k−14=0

⟹ 2(4)+2k−14=0

⟹ 8+2k−14=0

⟹ 2k−6=0

⟹ 2k=6.

Hence, k=3.