Question

2x²+Kx+2=0 has distinct real roots, find the value of k

urgently needed​

Answer 1

Step-by-step explanation:

given equation has real and distinct root

then

b^2-4ac > 0

k^2 -4 × 2 ×2 > 0

k^2 - 16 > 0

k^2 > 16

k >4 or -4