Question

2x2+Kx+3=0 find the value of k for each of the following quadratic equation so that they have two equal roots.​

Answer 1

Answer:

2x^2+Kx+3=0

for equal roots ,

d= 0

b^2-4ac=0

(k)^2 - 4 ( 2 ) ( 3 ) = 0

k^2 - 36 = 0

k^2 = 36

k = √36

k= 6