2x²- ( P + 1 ) x + P - 1 = 0
P = ?
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Since α + β = [p + 1] / 2 and αβ = [p – 1] / 2
It is given that α – β = αβ
⇒ (α – β)² = α²β²
⇒ (α + β)² – 4 αβ = α²β2²
⇒ [[p + 1] / 2]² – 4 [p + 1] / 2 = {[p – 1] / 2}²
⇒ [[p + 1] / 2]² – {[p – 1] / 2}² = 4 [p – 1] / 2
⇒ p = 2 (p – 1)
∴ p = 2
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