Question

2x²-x-1,4x²+8x+3 find the gcd​

Answer 1

Answer:

${2x}^{2} - x - 1 \\ = {2x}^{2} - 2x + x - 1 \\ = 2x(x - 1) + 1(x - 1) \\ = (x - 1)(2x + 1)$

${4x}^{2} + 8x + 3 \\ = {4x}^{2} + 6x + 2x + 3 \\ = 2x(2x + 3) + 1(2x + 3) \\ = (2x + 3)(2x + 1)$

So HCF = 2x + 1.

Answer 2

Answer:

this is correct...............