Question

2x2-x+1/8=0 find the answer by factorisation

Answer 1

Answer:

$2 {x}^{2} - x + \frac{1}{8} = 0 \\ \\ \\ 16 {x}^{2} - 8x + 1 = 0 \\ \\ \\ = > 16 {x}^{2} - 4x - 4x + 1 = 0 \\ \\ \\ = > 4x(4x - 1) - 1(4x - 1) = 0 \\ \\ = > (4x - 1)(4x - 1) = 0 \\ \\ \\ = > 4x = 1 \\ \\ x = \frac{1}{4}$

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Answer 2

Answer:

points please nedded them sorry for the answer...