Question

2x2-x+1/8
factorize this
​

Answer 1

Answer:

2(x - $\frac{1}{4}$)²

Step-by-step explanation:

ax² + bx + c = a(x - $x_{1}$)(x - $x_{2}$) , where $x_{1}$ and $x_{2}$ are roots of ax² + bx + c = 0

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2x² - x + $\frac{1}{8}$ = 0

D = (- 1)² - 4 × 2 × $\frac{1}{8}$ =  1 - 1 = 0

$x_{12}$ = (- (- 1)) / 2×2 = $\frac{1}{4}$

2x² - x + $\frac{1}{8}$ = 2(x - $\frac{1}{4}$)²