Math, asked by KurumiChan, 7 months ago

2x² - x - 10 by 2x² -11x + 15​

Answers

Answered by Anonymous
2

Step-by-step explanation:

\frac{(2x² - x - 10)}{(2x² - 11x + 15)}

\frac{2x²+4x-5x-10}{2x²-6x-5x+15}

\frac{2x(x+2)-5(x+2)}{2x(x-3)-5(x-3)}

\frac{(2x-5)(x+2)}{(2x-5)(x-3)}

\frac{(x+2)}{(x-3)}

Answered by sureshkumarjjr
0

Answer:

2x²-x-10/2x²-11x+15

2x²+4x-5x-10/2x²-6x-5x+15(by middle term splitting)

2x(x+2)-5(x+2)/2x(x-3)-5(x-3)

(2x-5)(x+2)/(2x-5)(x-3)

(x+2)/(x-3)

this is the answer.hope it help you

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