2x²- x+14, 5x -3x²+8,Subtract the given terms.
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Solution :
Given two expressions are,
First expression = 2x² - x + 14
Second expression = 5x - 3x² + 8
i ) Subtracting second expression
from first , we get
2x² - x + 14 - ( 5x - 3x² + 8 )
= 2x² - x + 14 - 5x + 3x² - 8
= 2x² + 3x² - x - 5x + 14 - 8
= ( 2 + 3 )x² + ( -1 - 5 )x + 6
= 5x² - 6x + 6
ii ) Subtracting first expression from
second expression, we get
5x - 3x² + 8 - ( 2x² - x + 14 )
= 5x - 3x² + 8 - 2x² + x - 14
= -3x² - 2x² + 5x + x + 8 - 14
= ( -3 - 2 )x² + ( 5 + 1 )x - 6
= -5x² + 6x - 6
••••
Given two expressions are,
First expression = 2x² - x + 14
Second expression = 5x - 3x² + 8
i ) Subtracting second expression
from first , we get
2x² - x + 14 - ( 5x - 3x² + 8 )
= 2x² - x + 14 - 5x + 3x² - 8
= 2x² + 3x² - x - 5x + 14 - 8
= ( 2 + 3 )x² + ( -1 - 5 )x + 6
= 5x² - 6x + 6
ii ) Subtracting first expression from
second expression, we get
5x - 3x² + 8 - ( 2x² - x + 14 )
= 5x - 3x² + 8 - 2x² + x - 14
= -3x² - 2x² + 5x + x + 8 - 14
= ( -3 - 2 )x² + ( 5 + 1 )x - 6
= -5x² + 6x - 6
••••
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