Question

2x²+x-4=0 find roots by using quadratic formula in short ans

Answer 1

Answer:

D=b^2-4ac

D=(1)^2-4(2)(-4)

D=1-(-32)

D=1+32

D=33

Now,

$\alpha = - b + \sqrt{d } \div 2a \\ \\ \beta = - b - \sqrt{d} \div 2a$

Therefore

$\alpha = - 1 + \sqrt{33} \div 4 \\ \beta = - 1 - \sqrt{33} \div 4$

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Answer 2

Answer:

x=-1+√33÷4 or x=-1-√33÷4 are the root of give quadratic equation

Step-by-step explanation:

comparing with ax²+bx+c=0

a=2,b=1,c=-4

b²-4ac=1²-4×2×(-4)

=1-8×(-4)

=1+32

=33

x=-b+-√b²-4ac÷2a

=-1+-√33÷2×2

=-1+-√33÷4

x=-1+√33÷4 or x=-1-√33÷4