Question

2x²+x-4=0 find the root​

Answer 1

On comparing the above equation with ax^2+bx+c=0 we get ,,,,

a = 2

b = 1

c = -4

b^2-4ac = ( 1 ) ^2 - 4 x 2 x -4

= 1 + 32

= 33 > 0

b^2-4ac > 0

x = -b ± √b^2-4ac / 2a

= - 1 ± √33 / 2 x 2

x = -1 ± √33 / 4

=> x = -1 - √33 / 4

=> x = √33 - 1 / 4

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