Question

2x2+x-4=0 find the roots of the following quadratic equations if they exist by the method of factorization​

Answer 1

Answer:

Method of completing the square,

Given equation is 2x

2

−x−4=0

The coefficient of x

2

is 2, make it 1 by dividing by 2 on both the sides.

i.e. x

2

−

2

x

−2=0

Transpose the constant term to the right.

x

2

−

2

x

=2

Add the square of half the coefficient of x on both sides.

x

2

−

2

x

+

16

1

=2+

16

1

(x−

4

1

)

2

=

16

33

The equation is of the form

a

2

=b

which implies

a=±

b

Therefore,

x−

4

1

=±

4

33

So, x=

4

1

+

4

33

or x=

4

1

−

4

Step-by-step explanation:

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Answer 2

Answer:

0 is the answer

Step-by-step explanation:

(2)(2)+x-4=0

4+X-4=0

4+X=0+4

4+X=4

X=4-4

X=0