Question

2x²+x+4=0
Plz ans this by completing the square method
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Answer 1

$\huge\bigstar\mathfrak\blue{\underline{\underline{SOLUTION:}}}$

${2x}^{2} + x - 4 = 0 \\ \\ = > {x}^{2} + \frac{x}{2} - 2 = 0 \\ \\ = > {x}^{2} + \frac{x}{2} + \frac{1}{4} - \frac{1}{4} - 2 = 0 \\ \\ = > [ {x}^{2} + \frac{x}{2} + ( \frac{1}{2} ) {}^{2} ] - 2 - \frac{1}{4} = 0 \\ \\ = > (x + \frac{1}{2} ) {}^{2} = 2 + \frac{1}{4} \\ \\ = > (x + \frac{1}{2} ) {}^{2} = \frac{9}{4} \\ \\ = > (x + \frac{1}{x} ) {}^{2} = ± \frac{3}{2} \\ \\ = > x + \frac{1}{2} = \frac{3}{2} \: and \: x + \frac{1}{2} = - \frac{3}{2} \\ \\ = > x = 1 \: \: and \: \: x = - 2$

hope it helps ☺️

Answer 2

HERE IS YOUR ANSWER IN IMAGE..❣️❣️⬆️⬆️