Question

2x²+x-6=0 do factorisation​

Answer 1

Answer:

$2 {x}^{2} + x - 6 = 0 \\ or. \: \:2 {x}^{2} + (4 - 3)x - 6 = 0 \\ or. \: \: 2{x}^{2} + 4x - 3x - 6 = 0 \\ or. \: \: 2x(x + 2) - 3(x + 2) = 0 \\ or. \: \: (x + 2)(x - 3) = 0 \\ \\ or. \: \: x + 2 = 0 \\ or. \: \: x = ( - 2) \\ \\ or. \: \: 2x - 3 = 0 \\ or. \: \: x = 3/2$

X = (-2) or, 3/2

It's your answer..

Answer 2

We are given the equation 2x² + x - 6 = 0

We need to factorise that equation.

For factorising any given equation, there are 3 methods:

1. Splitting the middle term.
2. Finding x by the formula x = (-b ± √D) ÷ 2a
3. Completing the square method.

Here we shall solve by splitting the middle term.

For splitting the middle term,

We need to find 2 numbers whose

• Product is 12 and
• Subtraction is 1

Those numbers are 4 and 3.

On factorising the equation:

2x² + x - 6 = 0

→ 2x² + 4x - 3x - 6 = 0

→ 2x(x + 2) - 3(x + 2) = 0

→ (2x - 3) (x + 2) = 0

So, the factors are:

• (2x - 3)
• (x + 2)