Question

2x2+x-6=0 roots by fractorisation
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Answer 1

Answer:

$2 {x}^{2} + x - 6 = 0 \\ = > 2 {x}^{2} + 4x - 3x - 6 = 0 \\ = > 2x(x + 2) - 3(x +2) = 0 \\ = > (2x - 3)(x + 2) = 0 \\ = > x = \frac{3}{2} \: or \: - 2$

Answer 2

Answer:

2x^+x-6=0

2x^+(4-3)x-6=0

2x^+4x-3x-6=0

2x(x+2)-3(x+2)=0

(x+2)(2x-3)=0

x=-2

x=3/2.

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