Question

2x2 +xy - y2 , -x2 + 2xy + 3y2 , 3x2- 10 xy + 4y2.​

Answer 1

Step-by-step explanation:

ANSWER

2x

2

+xy−y

2

,−x

2

+2xy+3y

2

and 3x

2

−10xy+4y

2

The sum of 2x

2

+xy−y

2

,−x

2

+2xy+3y

2

and 3x

2

−10xy+4y

2

is calculated as shown below

(2x2+xy−y

2

)+(−x

2

+2xy+3y

2

)+(3x

2

−10xy+4y

2

)

=2x

2

−x

2

+3x

2

+xy+2xy−10xy+3y

2

+4y

2

−y

2

We get,

=4x

2

−7xy+6y

2

Hence, the sum of 2x

^2

+xy−y

2

,−x

2

+2xy+3y ^2

and 3x ^2 −10xy+4y ^2 is 4x ^2−7xy+6y^2