Question

2x²+y²+8z²-2√2xy+4√2yz-8xz

Answer 1

Answer:

Step-by-step explanation:

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above expression can be written as,

(√2x)²+(-y)²+(-2√2z)²+2*(√2x)*(-y)+2(-y)(-2√2z)+2(-2√2x)(√2x)......(1)

Now acc to formula,

(a+b+c)²= a²+b²+c²+2ab+2bc+2ca

equation (1) becomes,

[(√2x)+(-y) +(-2√2z)]²=(√2x-y-2√2z)²

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Answer 2

Answer:

=(√2x)²+(y)²+(-2√2z)²+2(√2x) (-y) +2(-y) (-2√2z) +2(-2√2x) (√2z)

=(√2x-y-2√2z)²