Question

2x²+y²+8z²-2√2xy+4√2yz-8zx

Answer 1

Answer:

$2{x}^{2} + {y}^{2} + {8z}^{2} + 2 \sqrt{2xy} + 4 \sqrt{2yz} - 8zx \\ = { ( - \sqrt{2} x)}^{2} + {(y)}^{2} + {(2 \sqrt{2} z)}^{2} +2 ( - \sqrt{2} x)y + 2.y(2 \sqrt{2} z) + 2(2 \sqrt{2} z)( - \sqrt{2} ) \\ = {( - \sqrt{2}x + y + 2 \sqrt{2} z)}^{2}$

HOPE IT'LL HELP... :)

Answer 2

(-√2 x)^2+y^2 +(2√2 z)^2. -2√2xy+4√2yz-8zx

=(y-2√2 x+2√2z)^2

hope it helps you dude