Question

2x2+y2+8z2-2√2xy+4yz-8zx

Answer 1

(-root 2x)^2+(y)^2+(2root2z)^2+2 (-root2x)(y)+2 (y)(2root2z)+2 (-root2x)(2root2z)


= (-root2x + y+2root2z )^2
by using (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ac
hey mate I hope this helps you

Answer 2

I hope yourquestion is
$2x { }^{2} + y {}^{2} + 8z {}^{2} - 2 \sqrt{2} xy + 4 \sqrt{2} yz - 8zx$
I HOPE SO IT IS CORRECT QUESTION JUST CHECK YOUR QUESTION IF SUPPOSE YOUR QUESTION WAS CORRECT I WILL EDIT MY ANSWER...


(√2x)²+(-y)²+(-2√2z)²+2*(√2x)*(-y)+2(-y)(-2√2z)+2(-2√2x)(√2x)......(1)

Now acc to formula,
(a+b+c)²= a²+b²+c²+2ab+2bc+2ca
equation (1) becomes,
[(√2x)+(-y) +(-2√2z)]²=(√2x-y-2√2z)²

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