Question

2x²4tx+k=0 zeros are 4,-2 find t,k​

Answer 1

Answer:

t = 1 and k = - 16

Step-by-step explanation:

f(x) = ax² + bx + c = a(x - $x_{1}$)(x - $x_{2}$), where $x_{1}$ and $x_{2}$ are zeros of f(x)

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2(x - 4)(x + 2) = 2(x² - 2x - 8) = 2x² - 4x - 16

4t = 4 ===> t = 1

k = - 16

Answer 2

$The given quadratic equation is ;2x^{2} - 4kx + k = 0Clearly , we have ;a = 2b = -4kc = kWe know that ,The quadratic equation will have real and equal roots if its discriminant is equal to zero.= D = 0= (-4k)² - 4•2•k = 0= 16k² - 8•k = 0= 8k(2k - 1) = 0= k(2k-1) = 0= k = 0 , 1/2hence,The required values of k are 0 and 1/2$