Question

(2x²5x+7) from (3x²+48-6)​

Answer 1

Correct question:

Subtract $2x^{2}-5x+7$ from $3x^{2}+4x-6$.

Step-by-step explanation:

Now, $(3x^{2}+4x-6)-(2x^{2}-5x+7)$

• Remember the multiplication rule for symbols:

• $(+)\times (+)=(+)$

• $(+)\times (-)=(-)$

• $(-)\times (+)=(-)$

• $(-)\times (-)=(+)$

$=3x^{2}+4x-6-2x^{2}+5x-7$

• Rearrange the like terms and group them.

$=3x^{2}-2x^{2}+4x+5x-6-7$

$=(3-2)x^{2}+(4+5)x-(6+7)$

$=x^{2}+9x-13$

Answer:

The required subtraction is $x^{2}+9x-13$.

Answer 2

✮ Question

$\sf{Subtract\:\:2x^2-5x+7\:\:from\:\:3x^2+4x- 6}$

✮ Answer  

$\sf{x^2+9x-13}$

✮ Explanation

$\sf{\left(3x^2+4x-6\right)-\left(2x^2-5x+7\right)}$

$\sf{=3x^2+4x-6-\left(2x^2-5x+7\right)}$

$\sf{=3x^2+4x-6-2x^2+5x-7}$

$\sf{=3x^2-2x^2+4x+5x-6-7}$

$\sf{=x^2+4x+5x-6-7}$

$\sf{=x^2+9x-6-7}$

$\sf{=x^2+9x-13}$