(2x²y - 3y) (3xy - x)
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x=3−5–√−−−−−−√=6–25–√2−−−−−−√
Since 5=5∗1 and 6=5+1
x=5–√–12–√
Similarly y=5–√+12–√
Alao x2=3−5–√ and y2=3+5–√
Now given expression
=x(1+2y2+y4)−y(1–2x2+x4)
=x(1+y2)2−y(x2–1)2
=5–√–12–√(1+3+5–√)2−5–√+12–√(3−5–√–1)2
=12–√{(5–√–1)(21+85–√)−(5–√+1)(9−45–√)}
=2–√(15+45–√)
I hope you are understand my solution
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