Math, asked by bhogtayasraja, 6 months ago

2x²y-3yz²+4y² when x = 0 ,y = 2 and z = 1

Answers

Answered by hppatel919
0

Answer:

the answer of the question is 10.

Step-by-step explanation:

answer is absolutely right.

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Answered by dheeravathbhashya06
3

2x²y-3yz²+4y²

x=0, y=2and z=1

2(0)²(2)-3(2)(1)²+4(2)²

=0-6+16

=16-6

=10

here your answer

thank you

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