2x²y-3yz²+4y² when x = 0 ,y = 2 and z = 1
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0
Answer:
the answer of the question is 10.
Step-by-step explanation:
answer is absolutely right.
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Answered by
3
2x²y-3yz²+4y²
x=0, y=2and z=1
2(0)²(2)-3(2)(1)²+4(2)²
=0-6+16
=16-6
=10
here your answer
thank you
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