2x³-3x²-10x+5 divide by 2x-3
sanikanikam:
by using linear method
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The answer is
x^3-3/2x^2-6x+4=0
x^3-3/2x^2-6x+4=0
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2x-3)2x³-3x²-10x+5(x²-5 2x³-3x² (-) (+) ➖➖➖➖➖➖➖ ✖ -10x+5 -10x+15 (+) (-) ➖➖➖➖➖➖ ✖ -10 Quotient= x²-5 Remainder =-10 Hope it helps....
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