Question

2x³-3x²-17x+30 factories
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Answer 1

Answer:

x= -3

Step-by-step explanation:

let f( x) = 2x3- 3x2- 17x+ 30 .

so f(-3) = 2(-3) - 3(-3) - 17(-3) + 30 =

-54 -27 +51 +30 = -81 +81 = 0

thus, (x+3 ) is a factor of f( x)

if

(2x3- 3x2- 17x+ 30)÷ (x+3)

then the quotient is (2x2-9x+10) and the

remainder is (0).

2x3- 3x2- 17x+ 30=(x+3) (2x2- 4a-a 5x+10)

=(x+3) (2x2- 4x- 5x+10)

=(x+3) (2x(x-2)-5(x-2))-3

=(x+3) (2x-5)(x-2)

Answer 2

Step-by-step explanation:

first we have to find the factor of 30 and substitute to the equation. if it results in 0 ,this is one of the factor of the equation. since this equation is trinomial it has 3 factors.

2(2)cube -3(2)square-17(2)+30

16-12-34+30

4-34+30

4-4=0

hence x-2 is one of the factor of the equation.

to find the remaining factors. we have to divide it by x-2.

after dividing we

get the remainder 2x square +x-15.

2x square +6x-5x-15

2x(x+3)-5(x+3) (x-2)

(2x-5)(x+3)(x-2)

hence the factors of the equation are(x-2)(2x-5)(x+3)

.