2x³-3x²-17x+30 factories
Answers
Answer:
x= -3
Step-by-step explanation:
let f( x) = 2x3- 3x2- 17x+ 30 .
so f(-3) = 2(-3) - 3(-3) - 17(-3) + 30 =
-54 -27 +51 +30 = -81 +81 = 0
thus, (x+3 ) is a factor of f( x)
if
(2x3- 3x2- 17x+ 30)÷ (x+3)
then the quotient is (2x2-9x+10) and the
remainder is (0).
2x3- 3x2- 17x+ 30=(x+3) (2x2- 4a-a 5x+10)
=(x+3) (2x2- 4x- 5x+10)
=(x+3) (2x(x-2)-5(x-2))-3
=(x+3) (2x-5)(x-2)
Step-by-step explanation:
first we have to find the factor of 30 and substitute to the equation. if it results in 0 ,this is one of the factor of the equation. since this equation is trinomial it has 3 factors.
2(2)cube -3(2)square-17(2)+30
16-12-34+30
4-34+30
4-4=0
hence x-2 is one of the factor of the equation.
to find the remaining factors. we have to divide it by x-2.
after dividing we
get the remainder 2x square +x-15.
2x square +6x-5x-15
2x(x+3)-5(x+3) (x-2)
(2x-5)(x+3)(x-2)
hence the factors of the equation are(x-2)(2x-5)(x+3)
.